diff --git a/00.brainstorming-pedagogical-teams/45.synthesis-structuring/instructions-for-levels/30.beyond/annex.es.md b/00.brainstorming-pedagogical-teams/45.synthesis-structuring/instructions-for-levels/30.beyond/annex.es.md
index a9f001c9e..d318af371 100644
--- a/00.brainstorming-pedagogical-teams/45.synthesis-structuring/instructions-for-levels/30.beyond/annex.es.md
+++ b/00.brainstorming-pedagogical-teams/45.synthesis-structuring/instructions-for-levels/30.beyond/annex.es.md
@@ -215,44 +215,45 @@ Se ofrecen las siguientes categorías, pero para discusión, todas las ideas son
 ! *Discovery time : 30 minutes*<br>
 ! *Resolution time : 10 minutes*
 !
-! <details markdown=1>
+! <details>
 ! <summary>
 ! I choose it
 ! </summary>
 ! A lensball is a simple physical system: a sphere of glass of refractive index $`n=1.5`$ and of radius $`R=5\;cm`$.
-!
+! <br>
 ! A ball lensball is placed in front of a painting. Depending on the position of the observer or the camera, 
 ! the optical system (the sequence of simple optical elements crossed by light between the physical object
 ! and the observed image) that forms the image differs.
-!
+! <br>
 ! Observe the 3 images of the painting given by the lensball :
-!
+! <br>
 ! Image 1
-!
+! <br>
 ! ![](lentille-boule-1-transparence_L650.jpg)
-!
+! <br>
 ! Images 2 (the smallest) and 3
-!
+! <br>
 ! ![](lentille-boule-2-reflexions_L650.jpg)
-!
+! <br>
 ! For each image of the painting, can you identify the optical system, then specify `
 ! the characteristics of the various simple elements that constitute the system and their relative distances?
-!
+! <br>
 ! * _The resolution time is the typical expected time to be allocated to this problem if it was part of an examen for an optics certificate._ 
 ! * _The discovery time is the expected time required to prepare this challenge if you don't have practice. But take as much time as you need._
-!
 ! <\details>
+! <br>
 ! <details>
 ! <summary>
 ! Ready to answer M3P2 team questions for image 1?
 ! </summary>
-!
+! <br>
 ! <details>
 ! <summary>
 ! Where is the painting located?
 ! </summary>
 ! * The painting is located on the other side of the lens, in relation to you.
 ! </details>
+! <br>
 ! <details>
 ! <summary>
 ! What is the optical system giving the image of the painting?
@@ -261,6 +262,7 @@ Se ofrecen las siguientes categorías, pero para discusión, todas las ideas son
 ! * The optical system is composed of two spherical refracting surfaces, centered on the same optical axis.<br>
 ! <br>
 ! </details>
+! <br>
 ! <details>
 ! <summary>
 ! How do you characterize each of the single optical elements that make up this optical system, 
@@ -280,79 +282,83 @@ Se ofrecen las siguientes categorías, pero para discusión, todas las ideas son
 ! $DS2$ encountered by the light has the follwing characteristics :<br>
 ! $`\overline{S_2C_2}=-|R|=-5\;cm`$ , 
 ! $`n_{ini}=1.5`$ and $`n_{fin}=1`$
-!
+! <br>
 ! * Algebraic distance between $DS1$ and $DS2$ is : $`\overline{S_1S_2}=+10\;cm`$
-!
+! <br>
 ! </details>
+! <br>
 ! <details>
 ! <summary>
 ! If you had to determine the characteristics of the image (position, size), how 
 ! would you handle the problem?
 ! </summary>
-!
+! <br>
 ! * $`DS1`$ gives an image $`B_1`$ of an object $`B`$. This image $`B_1`$ for $`DS1`$ 
 ! becomes the object for $`DS2`$. $`DS2`$ gives an image $`B'1`$ of the object $`B_1`$
-!
+! <br>
 ! </details>
 ! </details>
-!
+! <br>
 ! <details>
 ! <summary>
 ! Ready to answer M3P2 team questions for images 2 and 3?
 ! </summary>
-!
+! <br>
 ! <details>
 ! <summary>
 ! Where is the painting located?
 ! </summary>
-!
+! <br>
 ! * The painting is located on the same side of the lens as you, behind you.
-!
+! <br>
 ! </details>
+! <br>
 ! <details>
 ! <summary>
-! 
+! <br>
 ! What are the two optical systems at the origin of the two images of the painting? And 
 ! can you characterize each of the single optical elements (+ their relative distances) 
 ! that make up each of these optical systems ?
 ! </summary>
-!
+! <br>
 ! * A first optical system $`OS1`$ is composed of a simple convexe spherical mirror 
 ! (the object is reflected on the front face of the ball lensball). Keaping the optical
 ! axis positively oriented in the direction of the incident light propagation on the lensball,
 ! the algebraic value of the mirror radius is : $`\overline{SC}=+5\;c`$.
-!
+! <br>
 ! * The second optical system $`OS2`$ is composed of three simple optical elements :<br><br>
 ! 1) The light crosses a spherical refracting surface $`DS1`$ with characteristics : 
 ! $`\overline{S_1C_1}=+|R|=+5\;cm`$ , $`n_{ini}=1`$ and $`n_{fin}=1.5`$.
-!
+! <br>
 ! 2) Then the light is reflected at the surface of the last lensball interface that
 ! acts like a spherical mirror of characteristics : $`\overline{S_2C_2}=-|R|=-5\;cm`$, 
 ! $`n=1.5`$.
-!
+! <br>
 ! 3) Finally the light crosses back the first interface of the lensball that acts 
 ! like a spherical refracting surface those characteristics are :
 ! $`\overline{S_3C_3}=+|R|=+5\;cm`$ , $`n_{ini}=1.5$ and $n_{fin}=1`$.
-!
+! <br>
 ! Relative algebraic distances between the different elements of $`OS2`$ are :
-!
+! <br>
 ! $`\overline{S_1S_2}=+10\;cm`$ and $`\overline{S_2S_3}=-10\;cm`$
-!
+! <br>
 ! </details>
+! <br>
 ! <details>
 ! <summary>
 ! Which image is associated with each of the optical systems?
 ! </summary>
-! 
+! <br>
 ! * It is difficult to be 100% sure before having made the calculations. 
-!
+! <br>
 ! </details>
+! <br>
 ! <details>
 ! <summary>
 ! Why do we had to take the picture in the darkness, with only the painting 
 ! illuminated behind the camera, to obtain images 2 and 3 ?
 ! </summary>
-!
+! <br>
 ! * At a refracting interface, part of the light incident power is refracted, 
 ! and part is reflected. For transparent material like glass and for visible light,
 ! the part of the reflected power is small. If the room had been homogeneously