From b96e77a19186fba34f22be17c35ae1d9bcab7c28 Mon Sep 17 00:00:00 2001
From: Claude Meny <claude.meny@irap.omp.eu>
Date: Wed, 3 Feb 2021 12:01:39 +0100
Subject: [PATCH] Update annex.fr.md

---
 .../03.lens/03.lens-beyond/annex.fr.md                         | 3 +--
 1 file changed, 1 insertion(+), 2 deletions(-)

diff --git a/01.curriculum/01.physics-chemistry-biology/03.niv3/02.geometrical-optics/05.paraxial-optics/02.paraxial-optics-simple-elements/03.lens/03.lens-beyond/annex.fr.md b/01.curriculum/01.physics-chemistry-biology/03.niv3/02.geometrical-optics/05.paraxial-optics/02.paraxial-optics-simple-elements/03.lens/03.lens-beyond/annex.fr.md
index 8e2c5acf1..0e1a19838 100644
--- a/01.curriculum/01.physics-chemistry-biology/03.niv3/02.geometrical-optics/05.paraxial-optics/02.paraxial-optics-simple-elements/03.lens/03.lens-beyond/annex.fr.md
+++ b/01.curriculum/01.physics-chemistry-biology/03.niv3/02.geometrical-optics/05.paraxial-optics/02.paraxial-optics-simple-elements/03.lens/03.lens-beyond/annex.fr.md
@@ -138,11 +138,10 @@ media_order: 'lentille-boule-orleans-1bis.jpg,lensball-brut-820-760.jpg,Einstein
 !  Taking into account that the image is reversed, the algebraic value of the apparent magnification is $`\overline{M_A}=-0.44`$.
 !
 ! * You could obtained directly this algebraic value of $`M_A`$ by considering algebraic lengthes and angles values in the calculations :<br><br> $`\overline{M_A}=\dfrac{\overline{\alpha'}}{\overline{\alpha}}`$ $`=\dfrac  {arctan\left(\frac{-0.017}{-0.175}\right)} {arctan\left(\frac{90}{-400}\right)}`$ $`=\dfrac{0.097}{-0.221}=-0.44`$
-!  </details>
 !
 ! ![](lentille-boule-orleans-1bis.jpg)<br>
 ! _Cathedral of Orleans (France)_
-!
+! </details>
 ! </details>
 ! </details>
 ! </details>