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Update cheatsheet.fr.md

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Claude Meny 5 years ago
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@ -761,9 +761,10 @@ $`=\;\dfrac{( 1+R)^2-( 1-R)^2}{( 1+R)^2+( 1-R)^2}`$
!!! $`( 1+R)^2=(1+0.04)^2=1,082`$ et $`( 1-R)^2=(1-0.04)^2=0,922`$ !!! $`( 1+R)^2=(1+0.04)^2=1,082`$ et $`( 1-R)^2=(1-0.04)^2=0,922`$
!!! !!!
!!! *$`\mathcal{V}`$*$`\;=\dfrac{( 1+R)^2-( 1-R)^2}{( 1+R)^2+( 1-R)^2}=\dfrac{1,082-0,922}{(1,082+0,922)}`$ !!! *$`\mathcal{V}`$*$`\;=\dfrac{( 1+R)^2-( 1-R)^2}{( 1+R)^2+( 1-R)^2}=\dfrac{1,082-0,922}{(1,082+0,922)}`$
$`\;=\dfrac{0,160}{(2,004)}\simeq0;08`$
!!! $`\;=\dfrac{0,160}{(2,004)}\simeq0;08`$
![lame-mince-faces-paralleles_nb_L600.jpg](lame-mince-faces-paralleles_nb_L600.jpg) ![lame-mince-faces-paralleles_nb_L600.jpg](lame-mince-faces-paralleles_nb_L600.jpg)
_[Nous recherchons une figure libre de droit]_
<!--===A termminer, reste pas grand chose pour une première mouture=== <!--===A termminer, reste pas grand chose pour une première mouture===

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