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@ -118,39 +118,6 @@ Sont proposées les catégories suivantes, mais à débattre : |
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!!!! *DIFFICULT POINT* (contribute, or indicate a difficult point of understanding) |
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!!!! |
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!! *BEYOND* (to contribute) |
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!! |
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!! *CULTURAL POINT* (contributor) |
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!! |
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!!! *DO YOU MASTER ?* |
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!!! <details markdown=1> |
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!!! <Summary> |
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!!! Describe the test |
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!!! </summary> |
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!!! The text of the test (and its images, figures, audio, video, etc ...) |
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!!! Question text |
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!!! <details markdown=1> |
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!!! <summary> |
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!!! Answer choice 1 |
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!!! </summary> |
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!!! Text if this answer 1 is chosen |
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!!! </details> |
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!!! <details markdown=1> |
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!!! <summary> |
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!!! Answer choice 2 |
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!!! </summary> |
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!!! Text if this answer 2 is chosen |
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!!! </details> |
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!!! <details markdown=1> |
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!!! <summary> |
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!!! Complete solution. |
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!!! </summary> |
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!!! text of the solution |
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!!! </details> |
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!!! </details> |
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##### Quelques exemples |
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@ -335,7 +302,7 @@ Sont proposées les catégories suivantes, mais à débattre : |
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! |
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! <details markdown=1> |
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! <summary> |
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! Ready to answer M3P2 team questions ? |
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! Ready to answer questions ? |
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! </summary> |
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! <!--question 1--> |
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! <details markdown=1> |
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@ -358,8 +325,10 @@ Sont proposées les catégories suivantes, mais à débattre : |
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! <summary> |
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! Describe the optical system for this use of the lensball. |
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! </summary> |
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! |
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! * The lensball breaks down into two refracting spherical surfaces sharing the same |
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! centre of curvature C and of opposite radius (in algebraic values). |
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! |
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! </details> |
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! <!--question 3--> |
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! <details markdown=1> |
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@ -380,12 +349,14 @@ Sont proposées les catégories suivantes, mais à débattre : |
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! for the position.<br> |
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! $`\overline{M_T}=\dfrac{n_{ini}\cdot\overline{SA_{ima}}}{n_{fin}\cdot\overline{SA_{obj}}}`$ |
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! for the transverse magnification. |
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! |
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! </details> |
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! <!--question 4--> |
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! <details markdown=1> |
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! <summary> |
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! How do you set down your calculations? |
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! </summary> |
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! |
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! * The optical axis is the straight line that joins the center C of the lens to my eye, |
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! positively oriented in the direction of light propagation light for that observation, |
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! so from the cathedral to my eye. |
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@ -406,6 +377,7 @@ Sont proposées les catégories suivantes, mais à débattre : |
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! $`\overline{M_T}=\dfrac{1.5\cdot\overline{S_2A'}}{\overline{S_2A_1}}`$ (équ. DS2b)<br><br> |
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! The missing link between these two sets of equations is :<br> |
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! $`\overline{S_2A_1}=\overline{S_2S_1}+\overline{S_1A_1}=\overline{S_1A_1}-\overline{S_1S_2}`$. |
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! |
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! </details> |
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! <!--question 5--> |
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! <details markdown=1> |
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@ -433,13 +405,13 @@ Sont proposées les catégories suivantes, mais à débattre : |
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! $`\overline {S_1A_1}=\overline {S_1F'_1}=+15cm`$. So we can directly use equation DS2a with :<br> |
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! $`\overline{S_2A_1}=\overline{S_2F'_1}=\overline{S_2S_1}+\overline{S_1F'_1}`$ |
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! $`=\overline{S_1F'_1}-\overline{S_1S_2}=+15-10=+5\;cm`$.. |
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! </details> |
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! |
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! <!--question 6--> |
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! </details> |
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! <details markdown=1> |
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! <summary> |
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! Where is the image and how tall it is ? |
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! </summary> |
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! |
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! * To perform calculation, you must choose a unic lenght unit in your calculation, |
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! here $`cm`$ or $`m`$. We choose $`m`$ below. |
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! * Equation DS1a gives :<br> |
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