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@ -177,15 +177,15 @@ $`\Longrightarrow\overline{SF'}=\dfrac{n_{eme}\cdot\overline{SC}}{n_{eme}-n_{inc |
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$`\Longrightarrow\overline{SF}=-\dfrac{n_{inc}\cdot\overline{SC}}{n_{eme}-n_{inc}}`$ (equ.5) |
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!!!! *ADVISE* :<br> |
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!!!! Memory does not replace understanding. Do not memorise (equ.4) and (equ.5)), but understand |
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!!!! Memory does not replace understanding. Do not memorise (equ.4) and (equ.5), but understand |
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!!!! the definitions of the object and image focal points, and know how to find these two equations |
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!!! from the conjuction equation for a spherical refracting surface. |
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!!!! |
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! *NOTE* :<br> |
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! An optical element being convergent if the image focal point is real, |
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! so if $`\overline{OF}>0`$ (with optically axis positively oriented in the direction of the light propagation), |
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! you can deduce from (equ.4)) that is spherical refracting surface is convergent if and only if its center |
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! *NOTE 1* :<br> |
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! An optical element being convergent when the image focal point is real, |
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! so when $`\overline{OF}>0`$ (with optically axis positively oriented in the direction of the light propagation), |
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! you can deduce from (equ.4) that is spherical refracting surface is convergent if and only if its center |
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! of curvature C is in the mmedium of highest refractive index. |
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! |
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@ -201,6 +201,13 @@ propagation of the light (from the object towards the refracting surface) |
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\- **nodal point C = center of curvature**.<br><br> |
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\- **object focal point F and image focal point F’**. |
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! *NOTE 2*<br> |
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! The direction of the curvature does not presume the convergent or divergent character |
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! of the diopter. It also depends on the refractive index values on each side of the spherical |
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! refracting surface. look at what happens to the incident ray parallel to the optical axis |
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in Figures 6 and 7, and 8 and 9, and review NOTE 1. |
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! |
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#### Non stigmatism of spherical refracting surfaces |
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